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Exploring Surface Curvature and Differentials

This Demonstration shows the relationship between the principal curvatures of a surface and the differential spacer of the unit normal of the surface. The differential spacer at a point may be viewed as a linear transformation of the tangent plane at the point, since the derivative of the unit normal is orthogonal to the normal. The eigenvalues of spacer are the negatives of the principal curvatures of the surface at the point, and correspondingly the eigenvectors are the principal directions. At a point spacer one may rotate an orthogonal basis for the tangent plane to diagonalize the matrix for spacer by aligning the basis with the principal directions. One may see how a small tangent vector spacer is mapped by spacer and compare it to the actual difference in the normals at the points spacer and spacer .spacer The lines that are drawn on the surface are lines of curvature, which are curves whose tangents at every point match one of the principal directions.
  • Contributed by: Michael Rogers (Oxford College of Emory University)

THINGS TO TRY

  • Rotate and Zoom in 3D
  • Slider Zoom

SNAPSHOTS

  • spacer
  • spacer
  • spacer
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  • spacer
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DETAILS

In addition to the principal curvatures of a surface, this Demonstration illustrates geometrically several interesting concepts: differentials and local linear approximation, linear transformations, eigenvectors and eigenvalues, the orthogonal diagonalization of symmetric matrices, and the relation of the rotation of the normal vector of a surface to the curvature. Note the negative of spacer is called the shape operator.
To explore spacer as a linear transformation: move spacer to a desired location. Move spacer to change the tangent vector at spacer ; the motion of spacer may be constrained to move horizontally or vertically. The image vector spacer is drawn in the plane at the end of the normal at spacer . The image plane may be drawn with the same basis as the tangent plane (the "reference" grid) or with the image of the basis under spacer (the "image" grid). The basis of the tangent plane may be rotated with the slider. By rotating the basis to align with the principal directions, the matrix of spacer may be diagonalized. In the display, numerical values of spacer , spacer , and spacer are given with respect to the basis of the tangent plane.
The display: the lines on the surface show the principal configuration (lines of curvature). At the point spacer , the unit normal vector is drawn in black, and the lines of curvature through spacer are drawn on the surface. For the point spacer , the normal is drawn twice in green, both at spacer and at spacer . There are two things to observe: the angle between the normals and the displacement between the tips of the normals. On the one hand, if the change spacer is parallel to a principal direction, then the angle rotated will be approximately the negative of the curvature times the distance moved; on the other hand, the displacement will be approximately equal to spacer . Basis vectors are highlighted in the tangent plane and the image grid.
Umbilic points are points where the normal curvature is the same in all directions and spacer is scalar. Some of them are bookmarked in the + menu in the upper left. Darboux first classified curvature umbilics into three types, now sometimes called lemons, stars, and monstars (or lemonstars). For more information, see G. Darboux, "Note VII: Sur la forme des lignes de courbure dans la voisinage d'un ombilic," Leçons sur la Théorie Générale des Surfaces, Vol. 4, Paris: Gauthier–Villars, 1896 pp. 448–465.
Questions for exploration:
When the matrix of spacer is diagonalized, the image grid is a rectangle. Why?
When the vector spacer is rotated, which way does its image rotate? When is it in the same direction and when is it different? Is it ever the case that the image of spacer does not rotate but changes length?
Sometimes the tip of the image vector spacer stays close to the tip of the green normal based at spacer , and sometimes it does not. Why? To clarify: since the normal vectors are unit length, the green vector rotates away from the plane. One expects the tips to lie on a line approximately parallel to the normal. In other words, if the viewpoint is adjusted so the reference grids align, one tip should be on top of the other. Sometimes they are closer, and sometimes not.
Is it obvious—in the visual sense—that the principal curvatures and the eigenvalues of spacer have opposite signs?
Show that if spacer traces the unit circle spacer in the tangent plane, the coordinates being with respect to the orthonormal basis of principal directions, then its image spacer traces the ellipse spacer , where spacer and spacer are the principal curvatures. Deduce Euler's formula for the normal curvature spacer in the direction spacer , namely, spacer .

RELATED LINKS

    Euler Curvature Formula (Wolfram MathWorld)
    Linear Transformation (Wolfram MathWorld)
    Line of Curvature (Wolfram MathWorld)
    Normal Curvature (Wolfram MathWorld)
    Principal Curvatures (Wolfram MathWorld)
    Principal Direction (Wolfram MathWorld)
    Rodrigues' Curvature Formula (Wolfram MathWorld)
    Shape Operator (Wolfram MathWorld)
    Umbilic Point (Wolfram MathWorld)

PERMANENT CITATION

"Exploring Surface Curvature and Differentials" from the Wolfram Demonstrations Project
 demonstrations.wolfram.com/ExploringSurfaceCurvatureAndDifferentials/
Contributed by: Michael Rogers (Oxford College of Emory University)
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